tag:blogger.com,1999:blog-4242439961617529545.post8047812084622111612..comments2024-03-27T21:10:45.791+00:00Comments on Resourceaholic: 5 Maths Gems #127Jo Morganhttp://www.blogger.com/profile/11919801458664779971noreply@blogger.comBlogger8125tag:blogger.com,1999:blog-4242439961617529545.post-18626315671319582092020-05-15T14:35:45.628+01:002020-05-15T14:35:45.628+01:00This one-> https://twitter.com/DannyKodicek/sta...This one-> <a href="https://twitter.com/DannyKodicek/status/1261276929023451136?s=20" rel="nofollow">https://twitter.com/DannyKodicek/status/1261276929023451136?s=20</a> Jo Morganhttps://www.blogger.com/profile/11919801458664779971noreply@blogger.comtag:blogger.com,1999:blog-4242439961617529545.post-11193268537810724432020-05-15T14:34:17.471+01:002020-05-15T14:34:17.471+01:00Hi all. Someone on Twitter suggested a wonderfully...Hi all. Someone on Twitter suggested a wonderfully elegant solution that I hadn't considered. Looking at the numbers, I suspect it's what Don had in mind. Read <a href="https://twitter.com/mathsjem/status/1261272877371920385" rel="nofollow">this thread</a>) and look at the Pythagoras solution.Jo Morganhttps://www.blogger.com/profile/11919801458664779971noreply@blogger.comtag:blogger.com,1999:blog-4242439961617529545.post-47934846465959404022020-05-11T18:11:48.541+01:002020-05-11T18:11:48.541+01:00Use the cosine rule to find cos of one angle. Then...Use the cosine rule to find cos of one angle. Then find the opposite side length in a right angled triangle for sin of the same angle. Then use A = 1/2 a b sin C .Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4242439961617529545.post-32499568336254936332020-05-11T14:50:33.560+01:002020-05-11T14:50:33.560+01:00Got it now (with help from colleague). Lovely prob...Got it now (with help from colleague). Lovely problem :)Charlottehttps://www.blogger.com/profile/01448133482825381459noreply@blogger.comtag:blogger.com,1999:blog-4242439961617529545.post-29497333014375816922020-05-11T14:08:07.921+01:002020-05-11T14:08:07.921+01:00It is five yes, but I cannot do it without a calcu...It is five yes, but I cannot do it without a calculator, so would love to know what I am missing thereCharlottehttps://www.blogger.com/profile/01448133482825381459noreply@blogger.comtag:blogger.com,1999:blog-4242439961617529545.post-52808281465684926142020-05-11T10:27:08.424+01:002020-05-11T10:27:08.424+01:00Was it 5?Was it 5?Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4242439961617529545.post-66205331269676459622020-05-10T16:47:23.124+01:002020-05-10T16:47:23.124+01:00Please could someone offer a solution to the Don S...Please could someone offer a solution to the Don Steward triangle task? I'm stumpedAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-4242439961617529545.post-21299853505781245372020-05-08T08:20:09.084+01:002020-05-08T08:20:09.084+01:00Thank you Jo, as always very insightfull and usefu...Thank you Jo, as always very insightfull and useful. The A level resources you mentioned are new to me, so I am off to explore those :) I have been following you for years and am always in owe of your work - how do you manage to do all this + teach + family. <br /><br />All the best,<br />Anna.Anonymousnoreply@blogger.com