tag:blogger.com,1999:blog-4242439961617529545.post4310203770064792290..comments2017-10-20T06:32:22.811+01:00Comments on Resourceaholic: New GCSE: FunctionsJoanne Morgannoreply@blogger.comBlogger7125tag:blogger.com,1999:blog-4242439961617529545.post-39463893538901611602017-04-13T08:02:15.688+01:002017-04-13T08:02:15.688+01:00First do the index: 4^(-1/2) = 1/2
Then do the mul...First do the index: 4^(-1/2) = 1/2<br />Then do the multiplication: 4 x 1/2 = 2<br />So the answer is 2.Joanne Morganhttps://www.blogger.com/profile/11919801458664779971noreply@blogger.comtag:blogger.com,1999:blog-4242439961617529545.post-54115947282626858222017-04-12T22:44:50.014+01:002017-04-12T22:44:50.014+01:00Please could you inform me on the answer to ' ...Please could you inform me on the answer to ' f(x) = 4x^-1/2 what is f(4). Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4242439961617529545.post-70288278521870239212017-01-23T11:00:56.351+00:002017-01-23T11:00:56.351+00:00Done! Done! Joanne Morganhttps://www.blogger.com/profile/11919801458664779971noreply@blogger.comtag:blogger.com,1999:blog-4242439961617529545.post-24225345961194177482017-01-23T04:13:22.722+00:002017-01-23T04:13:22.722+00:00Thank you for understanding - would really appreci...Thank you for understanding - would really appreciate it if the picture is taken off twitter? Apologies againBeth CHhttps://www.blogger.com/profile/08055675340210007710noreply@blogger.comtag:blogger.com,1999:blog-4242439961617529545.post-84291298440810222212017-01-22T22:29:16.385+00:002017-01-22T22:29:16.385+00:00No harm done. Thanks for getting in touch. I'm...No harm done. Thanks for getting in touch. I'm always happy for ideas to be shared with a wider audience, but it's best done in your own words. Please don't worry. Joanne Morganhttps://www.blogger.com/profile/11919801458664779971noreply@blogger.comtag:blogger.com,1999:blog-4242439961617529545.post-43059119791694086602017-01-22T22:00:20.371+00:002017-01-22T22:00:20.371+00:00Hi, sorry about the mix up with the my last post. ...Hi, sorry about the mix up with the my last post. I am new to blogging and did it subconsciously. I did not mean to use your words/ideas. Taken the post down with immediate effect. ThanksBeth CHhttps://www.blogger.com/profile/08055675340210007710noreply@blogger.comtag:blogger.com,1999:blog-4242439961617529545.post-69468411332933148082017-01-19T18:09:24.814+00:002017-01-19T18:09:24.814+00:00Thanks to David Butler (@DavidKButlerUoA) for his...Thanks to David Butler (@DavidKButlerUoA) for his post which describes a much more mathematically sound way to find an inverse function than the procedure described above. http://blogs.adelaide.edu.au/maths-learning/2017/01/19/finding-an-inverse-function/ Joanne Morganhttps://www.blogger.com/profile/11919801458664779971noreply@blogger.com